| | Group : Standards; Vitamin Derivatives; Vitamin K Deriva Group : Building Blocks; Amino Acids; Carbohydrates and Group : Building Blocks; Amino Acids; Tryptamines; Group : Building Blocks; Carbohydrates; Carbohydrates an Group : Building Blocks; Chiral Molecules; Vitamin Deriv Group : Building Blocks; Isotopic Labeled Analogues; Phe Group : Building Blocks; Miscellaneous; Fentanyls; Group : Building Blocks; Miscellaneous; Materials; Envir Group : Building Blocks; Miscellaneous; Vitamin Derivati Group : Building Blocks; Natural Products; Extracted; Group : Building Blocks; Standards; Miscellaneous; Envir Group : Building Blocks; Standards; Steroids; Controlled Group : Building Blocks; Steroids; Miscellaneous; Carboh Group : Building Blocks; Vitamin Derivatives; Vitamin K Group : Research Tools; Isotopic Labeled Analogues; Carb Group : Research Tools; Miscellaneous; Phthalates; Group : Research Tools; Molecular Biology; Neonicotinoid Group : Research Tools; Standards; Steroids; Group : Standards; Amino Acids/Peptides; Antibotics; Nat Group : Standards; Amino Acids/Peptides; Phenethylamines Group : Standards; Cannabis Constituents; Cannabinols; Group : Standards; Chiral Molecules; Cannabis Constituen Group : Standards; Dyes; Environmental Standards, Mutage Group : Standards; Fluorescent Reagents; Vitamin Derivat Group : Standards; Isotopic Labeled Analogues; Environme 1,1’-DIPHENYL-1,1',2,2',3,3',4,4',5,5',6,6'-13C12 CAS:D486984 Trade Name: ¹³C12H10 Formula: 104130-36-1 TRC-D486984-1mg [H][13C]1=[13C]([H])[13CH]=[13C]([H])[13C]([H])=[1 1MG 1,1’-DIPHENYL-1,1',2,2',3,3',4,4',5,5',6,6'-13C12 CAS:D486984 Trade Name: ¹³C12H10 Formula: 104130-36-1 TRC-D486984-2.5mg [H][13C]1=[13C]([H])[13CH]=[13C]([H])[13C]([H])=[1 2.5mg 1,1’-DIPHENYL-1,1',2,2',3,3',4,4',5,5',6,6'-13C12 CAS:D486984 Trade Name: ¹³C12H10 Formula: 104130-36-1 TRC-D486984-10mg [H][13C]1=[13C]([H])[13CH]=[13C]([H])[13C]([H])=[1 10mg 1,1’-DIPHENYL-1,1',2,2',3,3',4,4',5,5',6,6'-13C12 CAS:D486984 Trade Name: ¹³C12H10 Formula: 104130-36-1 TRC-D486984-5mg [H][13C]1=[13C]([H])[13CH]=[13C]([H])[13C]([H])=[1 5mg |